jgsugden
Commander
4320 Posts
    
Walnut Creek, CA
 | | 09/13/2006 10:03 AM |
| | What are the most dice you've rolled (or seen rolled) as part of a strike? I'm not including dice resulting from special/blade abilities (like warpstrike). Only the dice that are rolled as part of the actual strike damage to be inflicted on enemy units in the strike square... | |
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Lachlarlan_the_Mad
Sergeant
470 Posts
| | 09/13/2006 11:11 AM |
| | 19. 14 from a single power 2 creature. Gots ta love dem DHCs. | |
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froffenhoffer
Sergeant
702 Posts
| | 09/13/2006 12:22 PM |
| Posted By Lachlarlan_the_Mad on 09/13/2006 11:11 AM
19. 14 from a single power 2 creature. Gots ta love dem DHCs.
DHC's? | |
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Thus said froffenhoffer
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Lachlarlan_the_Mad
Sergeant
470 Posts
| | 09/13/2006 12:26 PM |
| | Darkheart Cottages. | |
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Gnolaum
Sergeant
854 Posts
| | 09/13/2006 1:16 PM |
| THe highest I've been able to work out is 53.
Most I've done is 21.
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Lachlarlan_the_Mad
Sergeant
470 Posts
| | 09/13/2006 2:14 PM |
| How did you get 53?
Â
I'm only coming up with 39 with 3xCarrion Spiker and the rest of the warband dead. | |
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Ragnaroque
Skirmisher
36 Posts
| | 09/13/2006 5:03 PM |
| How about a 56 dice attack?
You have 3 Carrion Spikers and a Forgeblind Punisher in the cell, with all of the rest of your warband in the graveyard. Your opponent has 3 Barbstriders lurking in the cell and you've just declared a strike phase...
3*(12+(1*3))+(8+(1*3))=56
Of course if you allowed the use of an Unsatied Ragedrake instead of the Punisher it increases to 58... | |
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XAos
Underboss
2403 Posts
London
| | 09/14/2006 7:10 AM |
| 58 Dice with Trample, Ouch...
Would 3 Carrion spikers & a Book of Nothing be considered more 
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Prince o the Raven Banner
Sergeant
606 Posts
| | 09/15/2006 2:08 AM |
| Posted By XAos on 09/14/2006 7:10 AM 58 Dice with Trample, Ouch... Would 3 Carrion spikers & a Book of Nothing be considered more
Ouch, I hope I never see this.
I've seen 29 rolled once, to kill my poor Genteel Husk.
Overkill maybe? Having more than 1 Punisher in a cell is just silly.
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PIGSNOT
349 Posts
| | 09/18/2006 12:11 AM |
| Posted By Prince o the Raven Banner on 09/15/2006 2:08 AM Posted By XAos on 09/14/2006 7:10 AM 58 Dice with Trample, Ouch... Would 3 Carrion spikers & a Book of Nothing be considered more Ouch, I hope I never see this. I've seen 29 rolled once, to kill my poor Genteel Husk. Overkill maybe? Having more than 1 Punisher in a cell is just silly.
Not if those Punishers are backing a book of nothing.
Imagine the blades rolled in that cell.
Talk about your warpstrikey goodness!!!
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mantic
Skirmisher
15 Posts
| | 09/20/2006 4:45 PM |
| Today I rolled 6 dice witha dreadmorph ogre resluting in 3 blades. The
dmg wasn't very high but I had a reaper in the cell below with a DHC.
Lets just say I dealt 27dmg alone with the ambush ability.
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froffenhoffer
Sergeant
702 Posts
| | 09/24/2006 1:43 PM |
| | Nice ambushing.. | |
Champion of Wildshaped druid in with natural spell!
Thus said froffenhoffer
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smriggin
Skirmisher
4 Posts
| | 09/24/2006 11:08 PM |
| Actually, I figured this out once -
3 Forgeblind Punishers and a Painmonger in a cell with a DarkHeart Cottage and 11 unengaged creatures. Your opponent has 3 barbstriders in the cell.
Each Punisher is 8+3+11 = 22
Painmonger is 7+3+11 = 21
22*3 + 21 = 87
As of first set, 87 dice is the highest you can have in a single cell in 1 attack.
Shawn
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mantic
Skirmisher
15 Posts
| | 09/25/2006 6:05 PM |
| 4 strider? you playing a multiplayer game?
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DMG
Sneak
107 Posts
Dallas
| | 09/26/2006 3:56 AM |
| Posted By mantic on 09/25/2006 6:05 PM
4 strider? you playing a multiplayer game?
er....
Posts where my brain totally derailed have been deleted - thanks mantic! Apparently my brain confused max number of minis allowed in warband with max number of minis allowed in a cell and ran with it. Silly brain - need a new one. Anyway - my original point was that the DHC doesnt add its bonus to each mini - only to the attack as a whole so smriggin's math is quite a bit off. His example tops off at 54 dice I believe slightly edged out by the Cariion Spiker example above by 2 measly dice.
Sure wish DHC worked like that but it dont.
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Ragnaroque
Skirmisher
36 Posts
| | 11/03/2006 3:17 PM |
| As I was walking to work tonight, I was thinking about this subject with regard the new toys we have gained in Baxar's War. I haven't put a whole lot of thought into it, and given the premise that any situation, no matter how unfeasible is allowed, I've come up with a 73 dice attack. The question is a) what is the situation I've come with, and b) can you beat it? | |
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froffenhoffer
Sergeant
702 Posts
| | 11/05/2006 3:56 AM |
| 3 drakes=30, + the 8 damage passion beater(3 ,+dhc+11 unengadged(49)+3 empowering maidens nearby(61)+3 barbstriders of enemy= 70! drat. I could do it for multiplayer with another strider in the cell for 73....your thinking of 4 maidens?? if so its illegal.. | |
Champion of Wildshaped druid in with natural spell!
Thus said froffenhoffer
The Official through the heart, and im to blame archer. | |
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Faragdar the Wise
Commander
3530 Posts
Albuquerque, NM, USA
| | 11/05/2006 6:26 PM |
| | Actually, you got it froffenhoffer. 3 Barbstriders adds a total of 12 attack dice (inciter 1 * 3 barbstriders * 4 attackers). That's 73. So, is there a way to get more? I haven't come up with a higher number, yet. | |
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EldritchSoul
Warrior
324 Posts
| | 01/03/2007 8:18 PM |
| when the swordstrider comes out, the dice will go even higher
you have:
swordstrider
swordstrider
swordstrider
ragedrake
Cottage
(11 unengaged, 3 adjacent enraging maidens)
they have:
barbstrider
Barbstrider
Barbstrider
your ragedrake is at 16+
3 swordstriders each at 22
so 86+11 from the cottage... 97 dice
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Teflon Jeff
Warlord
7675 Posts
Sector 2814
| | 01/05/2007 7:45 AM |
| You guys do realize that the cottage only adds total dice to the attack, not each creatures power, right? So most of these totals are way off.
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EldritchSoul
Warrior
324 Posts
| | 01/05/2007 9:45 AM |
| these latest totals have only included the +11 once.
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jgsugden
Commander
4320 Posts
Walnut Creek, CA
| | 01/05/2007 1:35 PM |
| | Back to the original question: How many dice have you seen rolled as part of a strike? No theory here: What have you seen in practice? | |
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Ridureyu
Underboss
1622 Posts
| | 01/27/2007 3:10 AM |
| I just got a 24-dice-attack off in a game I played. It was in the 2-score cell, and contained a Dreadmorph ogre (6), Little Charmer (7), Infernal Gothic (5), and Equitar (6). I did some attracting, and killed most of my opponent's remaining forces. his deathblow was able to barely disrupt the Gothic.
Amusingly, it ultimately was worth less than two rounds previous, in which the Dreadmorph and FGothic were in the cell directly beneath it (engaged with a bunch of enemies), the Charmer was in my portal (engaged to an enemy I had disrupted there), and the Equitar was halfway into the sidelines. In THAT combat, the Charmer killed her enemy, the Gothic and Dreadmorph together lured/expelled, and killed 2, and the Equitar moved to engage the expelled enemy. This set up the next round, in which the Dreadmorph and Gothic joined the Equitar in the center cell, and the Charmer moved closer. After that, the middle cell was MINE, BABY!
I had a Slaughterwheel running around, which killed one and skirmished itself around. there was much death. | |
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Ridureyu
Underboss
1622 Posts
| | 01/27/2007 3:10 AM |
| | double post. | |
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forkedmoon
Underboss
1305 Posts
| | 01/29/2007 8:30 AM |
| | I managed to get to roll 15 during an Edge Tournament and scored 0 damage along with 5 useless blades. Followed that up with 11 later getting only 2 damage. And yes my dice do have numbers on them! | |
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jacksonm
Warlord
5560 Posts
River City
| | 01/29/2007 8:42 AM |
| | 24 is my top dice total. Very much overkill at the time. | | | |
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forkedmoon
Underboss
1305 Posts
| | 01/29/2007 10:05 AM |
| | I thought 15 was overkill when I only needed 4 damage to make a kill and take the round! | |
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Teflon Jeff
Warlord
7675 Posts
Sector 2814
| | 02/01/2007 3:28 PM |
| 25 Dice. Tri-color Rocket Boots, with Drake, Eater, and Double Knight's.
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stckcrsh
Skirmisher
5 Posts
| | 03/29/2007 1:16 AM |
| i just wanted to add that with three sword striders in a cell with a ragedrake surrounded by three maidens and three barbstriders makes a 97
then in an adjacent cell you have 4 warmongers from the anvilborn set which will bring your total to 416 dice (each warmonger has a power of 104=7+97)
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froffenhoffer
Sergeant
702 Posts
| | 03/29/2007 4:41 AM |
| | yeah, warmongers can do pretty sick things// | |
Champion of Wildshaped druid in with natural spell!
Thus said froffenhoffer
The Official through the heart, and im to blame archer. | |
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zxqueb
Skirmisher
13 Posts
| | 03/29/2007 7:23 AM |
| | Unfortunately you can only have 3 warmongers. 312 is not shabby though. Of course, if you factor this in the portal with no stacking limit, you can get 3 drakes, 3 maidens, 3 swordstriders 3 growlths and a world eater (with of course, the 3 enemy barb striders) next to the 3 warmongers brings the whole thing up to a total of 585 unless my math is off. | | | |
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kbales
Warrior
296 Posts
Edmonton, Alberta
| | 04/01/2007 8:16 AM |
| Posted By smriggin on 09/24/2006 11:08 PM
Actually, I figured this out once -
3 Forgeblind Punishers and a Painmonger in a cell with a DarkHeart Cottage and 11 unengaged creatures. Your opponent has 3 barbstriders in the cell.
Each Punisher is 8+3+11 = 22
Painmonger is 7+3+11 = 21
22*3 + 21 = 87
As of first set, 87 dice is the highest you can have in a single cell in 1 attack.
Shawn
I don't think you add the 11 dice to each creature...so I believe you would only get the +11 dice one time. So that would be 33 dice from the forgeblind punishers +10 from Painmonger, +11 from the DHC = 54 dice. It would be nice if it worked the other way though.
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DMG
Sneak
107 Posts
Dallas
| | 04/26/2007 5:02 AM |
| Posted By zxqueb on 03/29/2007 7:23 AM
Unfortunately you can only have 3 warmongers. 312 is not shabby though. Of course, if you factor this in the portal with no stacking limit, you can get 3 drakes, 3 maidens, 3 swordstriders 3 growlths and a world eater (with of course, the 3 enemy barb striders) next to the 3 warmongers brings the whole thing up to a total of 585 unless my math is off.
this is funny -
Each creature in the Portal gets +6 from Maidens and Barbstriders
3 Omen Locusts @ (6+3)x3=27
3 Ragedrakes @ (6+10)x3=48
3 Caged Grawlths @ (6+9)x3=45
2 Swordstriders (mimic Drakes AFTER bonus)@ (6+16)x2=44
3 Maidens @ (2+2)x3=12
The third Swordstrider is in with the Warmongers and so Mimics their 166 dice for a grand total of 664!
I knew we could get it over 600!
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Whym
Skirmisher
3 Posts
| | 04/26/2007 4:39 PM |
| Unfortunately, Mimic and Grand Melee only function when the pieces are chosen as attackers.
So, if you have in...
Cell 2 (Portal, adjacent to Cell 1):
3x Ragedrake (10+6)x3=48
3x Maiden - Enraged (2+5)x3=21
3x Caged Grawlth (9+6)x3=45
3x Omen Locust (3+6)x3=27
2x Forgeblind Punisher (8+6)x2=28
3x Enemy Barbstrider
Total = 169
Cell 1 (combat cell):
3xWarmonger (169+3)x3=516
1x Swordstrider (172+3)=175
1x Enemy Fig
Total = 691
Having the barbstriders in the portal gives an additional 168 dice as opposed to only 29 if they were in the combat cell with a Cottage.
I think that looks about rght. Still over 600. | | | |
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DMG
Sneak
107 Posts
Dallas
| | 04/27/2007 10:24 AM |
| Posted By Whym on 04/26/2007 4:39 PM Unfortunately, Mimic and Grand Melee only function when the pieces are chosen as attackers.
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zxqueb
Skirmisher
13 Posts
| | 05/02/2007 7:56 AM |
| Posted By Whym on 04/26/2007 4:39 PM Unfortunately, Mimic and Grand Melee only function when the pieces are chosen as attackers.
So, if you have in...
Cell 2 (Portal, adjacent to Cell 1):
3x Ragedrake (10+6)x3=48
3x Maiden - Enraged (2+5)x3=21
3x Caged Grawlth (9+6)x3=45
3x Omen Locust (3+6)x3=27
2x Forgeblind Punisher (8+6)x2=28
3x Enemy Barbstrider
Total = 169
Cell 1 (combat cell):
3xWarmonger (169+3)x3=516
1x Swordstrider (172+3)=175
1x Enemy Fig
Total = 691
Having the barbstriders in the portal gives an additional 168 dice as opposed to only 29 if they were in the combat cell with a Cottage.
I think that looks about rght. Still over 600.
Â
Cell 2 (Portal, adjacent to Cell 1):
3x Ragedrake (10+6)x3=48
3x Maiden - Enraged (2+5)x3=21
3x Caged Grawlth (9+6)x3=45
3x Omen Locust (3+6)x3=27
2x Forgeblind Punisher (8+6)x2=28
3x Enemy Barbstrider
Total = 169
Cell 1 (combat cell):
3xWarmonger (169+7+3)x3=537
1x Swordstrider (179+3)=182
1x Enemy Fig
Total = 719
This is fun!Â
Now can we break 800?
Z | | | |
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Whym
Skirmisher
3 Posts
| | 05/02/2007 11:21 AM |
| Posted By zxqueb on 05/02/2007 7:56 AM
If I recall correctly, the warmongers also get their own 7 dice each in addition to the dice taken from cell #2.  That makes it break down like this:
*gasp* I forgot to add in the 'monger's 7? 
Good catch. Thanks. | | | |
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zxqueb
Skirmisher
13 Posts
| | 05/04/2007 8:27 AM |
| Thanks to Pipgamer for letting me in on this combo -- highly unlikely to be sure, but still awesome:
Cell 2 (Portal, adjacent to Cell 1):
3x Ragedrake (10+6)x3=48
3x Maiden - Enraged (2+5)x3=21
3x Caged Grawlth (9+6)x3=45
3x Omen Locust (3+6)x3=27
1x warlust satyr (6+6) = 12
1x shard troll (2+6) = 8
3x Enemy Barbstrider
Total = 161
Cell 1 (combat cell):
3xWarmonger (161+7+3)x3=513
1x Swordstrider (171+3)=174
3x Enemy dryads
Strike actions for two turns (1 skipped spawn) yielding all blades = 848 x 4 = 3392 blades to be used in the next phase's shard troll attack.
Total (with dryad pump, but before inish roll is factored in) = 3401
Dude. Those barb striders are going to die!
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DMG
Sneak
107 Posts
Dallas
| | 05/04/2007 10:57 AM |
| LOL! well - once again there's a problem. Warmongers text states explicitly "... it gains all the blade abilities of allies in target adjacent cell and gets +X power, where X is the total power of allies in that (the adjacent) cell." So he cant add to his buddies in the combat cell.
But now lets make that shard troll useful and imagine I have a War Eagle in my reserves and the rest of opponents band is in his portal.
3x Ragedrake (10+6)x3=48
3x Maiden - Enraged (2+5)x3=21
3x Caged Grawlth (9+6)x3=45
2x Omen Locust (3+6)x2=18
1x warlust satyr (6+6) = 12
1x shard troll (2+6) = 8
3x Enemy Barbstrider
Total = 152 Cell 1 (combat cell): 3xWarmonger (152+3)x3=456
1x Swordstrider (155+3)=158
3x Enemy dryads + redcap
=614 dice
Double strike for 2 turns with no spawn in between and 25 damage and the rest all blades (and he whiffs on all his strikes/deathblows, of course and for some reason leaves everyone grouped in this portal-LOL) = 2421 dice for Shard Troll after he gets teleported into enemy portal.
Something tells me this will never happen - ya think? LOL | | | |
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zxqueb
Skirmisher
13 Posts
| | 05/04/2007 12:25 PM |
| Posted By DMG on 05/04/2007 10:57 AM LOL! well - once again there's a problem. Warmongers text states explicitly "... it gains all the blade abilities of allies in target adjacent cell and gets +X power, where X is the total power of allies in that (the adjacent) cell." So he cant add to his buddies in the combat cell.
Um... I'm not sure why you think it wouldn't work. The allies are in the portal, adjacent to the warmonger... same as in the other setups. The warmonger clones the allies power and the multiblade battle energize. Then he generates blades for 4 strike phases, putting them into energize. Â
The real attack happens with the shard troll. | | | |
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